Question

X2 - root 2 -12 find the zeros

Answer 1

Solution :-

There is a mistake in the question , it should be :-

$x^2 - \sqrt{2} \bold{x} - 12 \bold{= 0}$

Now we have got the Quadratic formula :-

$x = \dfrac{ -b \pm\sqrt{ b^2 - 4ac}}{2a}$

By putting respective values

$x = \dfrac{ -\sqrt{2} \pm\sqrt{ \sqrt{2}^2 - 4(1)(-12)}}{2(1)}$

$= \dfrac{ -\sqrt{2} \pm\sqrt{ 2 + 48 }}{2}$

$x = \dfrac{ -\sqrt{2} \pm\sqrt{50}}{2}$

$x = \dfrac{ -\sqrt{2} + \sqrt{50}}{2} \: and\: \dfrac{ -\sqrt{2} + \sqrt{50}}{2}$