Math, asked by srivastavmiti, 4 days ago

x²-(root under2+1)x+root2=0​

Answers

Answered by biswasarnab2005
0

Answer:

your answer is here, read carefully

Attachments:
Answered by vedthakar004gmailcom
0

Answer:

(x -  \sqrt{2} )(x - 1)

step by step explanation:

 {x}^{2}  - ( \sqrt{2}  + 1)x +  \sqrt{2}  = 0 \\  {x}^{2}  -  \sqrt{2} x  -  x +  \sqrt{2}  = 0 \\ x(x - 1) -  \sqrt{2} (x - 1) = 0 \\ (x - \sqrt{2} )(x - 1)

MARK AS BRAINLIEST <3

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