x2(square) +1=0 find the vaue of x ( root never come in
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2
x²+1=0
x²= 0-1
x²= -1
x = √-1
x = undefined
x²= 0-1
x²= -1
x = √-1
x = undefined
Answered by
0
x^2 +1 =0
x^2 = -1
x = root-1
answer is that - sign never comes inside the root so this answer will not be defined....
x^2 = -1
x = root-1
answer is that - sign never comes inside the root so this answer will not be defined....
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