Question

x2
$x { }^{2} + 2x - 5 = 20$
+2x_5=20​

Answer 1

So I assume I’m supposed to solve the equation? Ok, here goes.
x^2+2x-5=20
x^2+2x=25
x^2+2x+(1)^2=25 + 1
(x+1)^2=26
x+1= + or - root 26
x+1=+root26 or x+1=-root 26
x=root 26-1 or x=-1-root26