Question

(x² - x + 1)²

Find the value. ​

Answer 1

Answer:

refer to the attachment also thank you for 50 points

Answer 2

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CONCEPT:-

In this query, we will first use the formula- (aᒾ+bᒾ+cᒾ) = aᒾ+bᒾ+cᒾ+ 2(ab) + 2(bc) + 2(ca). Then we will replace the value of a,b&c. After doing that we will use the BODMAS rule.

Formula used-

$\small\tt(a + b + c)^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab) + 2(bc) + 2(ca)$

Value of-

$\tt a = {x}^{2} ,\: b = - x ,\: c = 1 \}given$

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$\small \sf (a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab) + 2(bc) + 2(ca)$

$\tt( {x}^{2} - x + 1 {)}^{2} = ( {x}^{2} {)}^{2} + ( { - x}^{2} ) + (1 {)}^{2} + 2( {x}^{2} {)} ( - x) + 2( - x)(1) + 2(1)( {x}^{2} )$

$\tt ( {x}^{2} - x + 1 {)}^{2} = {x}^{4} + {x}^{2} + 1 - 2 {x}^{3} - 2x + 2 {x}^{2}$

$\tt ( {x}^{2} - x + 1 {)}^{2} = {x}^{4} - 2 {x}^{3} + 3 {x}^{2} - 2x + 1$

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