x²+x+1÷root2 = 0
please answer fast
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Answer:
take lcm=√2
then equation will be
(√2x²+√2x+1)/√2=0
by cross multiplication
√2x²+√2x+1=0
First check it's discrimination=b²-4ac
√2²-4×2×1
2-4√2<0
so this equation have no real root or zeros
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Step-by-step explanation:
the square: x2-(√2+1)x+√2=0. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. Find two numbers whose sum is 27 and product is 182. Two water taps together can fill a tank in 938 hours.
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