X²+x = -1 then x³-1 =?
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Answered by
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Answer:
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Step-by-step explanation:
x²+x=-1, middle term spread
then,
x²+x+1=0
x²+x+x+1=0
x(x+1)-1(x+1)=0
then, two values of x
(x-1) (x+1)
x=1 ,x=-1
x³-1=(1)³-1= 1-1= 0
Answered by
0
Step-by-step explanation:
cube both sides
(x² + x)³=(-1)³
[(a+b)³ = a³+ b³+ 3ab(a+b)]
x⁶ + x³ + 3x² × x(x² + x) = -1
x⁶ + x³ - 3x³ = -1
x³(x³+1-3) = -1
x³(x³-2) = -1
x³-1 = 0
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