x² -(x+1)(x+2)/5x+1=6
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=> x² - [(x + 1)(x + 2)] / 5x + 1 = 6
=> x² - [x(x+2)+1(x + 2)] / 5x + 1 = 6
=> x² [x² + 2x + x + 2] /5x + 1 = 6
=> x²- x² 3x - 2/ 5x + 1 = 6
=> -3x - 2 / 5x + 1 = 6
=> -3x - 2= 6(5x + 1)
=> -3x 2 = 30x+6
=> −2 − 6 = 30x + 3x
=> 33x = -8
=> X = (-8)/33
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