Math, asked by lorront64, 6 months ago

(x² + x +1) (x2 -x + 1).​

Answers

Answered by gugan64
9

Answer:

 \sf { ({x}^{2}  + x + 1)}^{2}

 \sf  {x}^{2 ^{2} }  +   {x}^{2}  +  {1}^{2}  +  {x}^{2}  \times x + x \times 1 +  {x}^{2}

 \sf {x}^{4}  +  {x}^{2}  + 1 +  {x}^{3} + x +  {x}^{2}

Answered by chaitalibhowmik12345
0

Answer:

 {x}^{2} ( {x}^{2}  - x + 1) + x( {x}^{2} - x + 1) + 1( {x}^{2} - x + 1)

 =  {x}^{4}  -  {x}^{3}  +  {x}^{2}  +  {x}^{3} -  {x}^{2} + x +  {x}^{2}  - x + 1

 =  {x}^{4}  +  {x}^{2}  + 1

Hope it helps you.

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