Question

x2+x-12 factorise it

Answer 1

${x}^{2} + x - 12 \: can \: be \: factorised \: by \: splitting \: te \: middle \: term.$
${x}^{2} + x - 12 \\ sum \: = 1. \\ product = - 12.$
${x}^{2} + x - 12. \\ = {x}^{2} + 4x - 3x - 12. \\ = x(x + 4) - 3(x + 4). \\ = (x + 4)(x - 3).$
$therefore \: (x + 4) \: and \: (x - 3) \: are \: the \: factors \: of \: {x}^{2} + x - 12.$

Answer 2

IN the above question given that

The equation is $X^{2} +X-12$

we have to factorize the above equation

We are  solving in the following way

consider the given expression

$X^{2}+X-12\\X^{2} +4X-3X-12\\X(X+4)-3(X+4)\\(X+4)(X-3)$

Hence the required factorization is

$(X+4)(X-3)$

Note; The given equation should be

$X^{2}+X-12$ .