x² - x - 12 split the middle term
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Answered by
6
x² - x - 12
= x² - (4-3)x - 12
= x² - 4x + 3x - 12
= x(x-4)+ 3(x-4)
=(x+3)(x-4)
= x² - (4-3)x - 12
= x² - 4x + 3x - 12
= x(x-4)+ 3(x-4)
=(x+3)(x-4)
Answered by
3
x^2 - x - 12 = 0
x^2 -(4-3)x - 12 = 0
x^2 -4x + 3x - 12 = 0
x(x-4) +3(x+4) = 0
(x-4)(x+3) = 0
x = 4 OR x = -3
i hope this will help you
-by ABHAY
x^2 -(4-3)x - 12 = 0
x^2 -4x + 3x - 12 = 0
x(x-4) +3(x+4) = 0
(x-4)(x+3) = 0
x = 4 OR x = -3
i hope this will help you
-by ABHAY
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