(x²-x-12) ( x-4) what's the answer plsss
Answers
Answered by
2
Answer:
X^2-X-12=0
X^2–4X+3X-12+0
X(X- 4) +3 (X- 4) =0
(X+3) (X-4) =0
Hence X+3=0 ; X= -3
X-4 = 0 ; X=4
Value of X = -3 & 4
Answered by
0
Answer:
x^3-5x^2-8x+48
explanation:
multiplying (x²-x-12) ( x-4)
so that we get x^3-x^2-12x-4x^2+4x+48
adding and subtracting we get
x^3-5x^2-8x+48
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