Question

x2+x-182=0
$x2 +x - 182 = 0$

Answer 1

Here is your answer



x² + x - 182

x² + 14x - 13x - 182

x ( x + 14 ) - 13 ( x + 14 )

( x + 14 ) ( x - 13 )



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Answer 2

Heya !!!


X² + X - 182



X² - 13X + 14X - 182


X ( X - 13 ) + 14 ( X - 13 )


( X - 13 ) ( X + 14 )



( X - 13 ) = 0 OR ( X + 14 ) = 0


X = 13 OR X = -14



Hence,


13 and -14 are two zeroes of the given quadratic polynomial.


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