Math, asked by sahithibh, 5 months ago

(x2 + x)2 - 8 (x2 + x) + 12 = 0​

Answers

Answered by Vedantlambade85
0

Step-by-step explanation:

= (2x + 2) 2 - 8 (2x + x) + 12 = 0

2 - 8 (2x + x) + 12 = 0= (4x + 4) - (16x + 8x) + 12 = 0

(4x + 4) - (16x + 8x) + 12 = 0= (4x + 4) - ( 16x + 8x) = -12

(4x + 4) - ( 16x + 8x) = -12= (4x) - (16x + 8x) = -12-4

(16x + 8x) = -12-4 = (4x) - (16x + 8x) = -16

(4x) - (16x + 8x) = -16= (4x) - (24x) = -16

(4x) - (24x) = -16= -(20x) = -16

-(20x) = -16= -x = -16/20

-(20x) = -16= -x = -16/20= - x = -4/5

-(20x) = -16= -x = -16/20= - x = -4/5= x = -4/-5

= (x = 4/5 )

Answered by Adarshtrivedi09
1

Step-by-step explanation:

(2x + x)2 - 8(2x + x) + 12 = 0  \\ (4x + 2x)( - 16x - 8x) + 12 = 0 \\ (6x)( - 24x) + 12 = 0 \\ 6x - 24x =  - 12 \\  - 18x =  - 12 \\ x =  - 12   \\ \frac{ - 12 }{- 18}  =  \frac{2}{3}  \:  \:  \:  \: answer \:

so simple you can do this

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