Question

(x²-x)²-8(x²-x)+12 factorise​

Answer 1

(x²x)²-8 (x²-x)+12

Let x²-x=y

y²-8y+12

y²-6y-2y+12

y (y-6)-2 (y-6)

(y-6) (y-2)

Putting the value of y

(x²-x-6) (x²-x-2)

(x²-3x+2x-6) (x²-2x+x-2)

[x (x-3)+2 (x-3)] [x (x-2)+1 (x-2)]

(x-3) (x+2) (x-2) (x+1)

Answer 2

Answer:

(x-3) (x+2) (x-2) (x+1)

Step-by-step explanation: