Question

x2-x-2=
pleas help me​

Answer 1

Answer:

Answer is attached above please refer to it

Answer 2

Unable to get your question...Though, the answer to both is as follows:

If your question is x² - x⁻²

Answer: $= x^{-2} (x^2+ 1)(x+1)(x-1)$

Solution:

= x² - x⁻²

$= x^2 - (\frac{1}{x}) ^2$

$= (x + \frac{1}{x} ) (x - \frac{1}{x})$                               [ a² - b² = (a + b) (a - b) ]

$= (\frac{x^2 + 1}{x})(\frac{x^2-1}{x} )$                                  [ L.C.M.]

$= \frac{(x^2 + 1)(x^2 -1)}{x^2}$

$= \frac{(x^2 + 1)(x^{2} - 1^2)}{x^2}$

$= \frac{(x^2 + 1)(x + 1) (x-1)}{x^2}$                               [ a² - b² = (a + b) (a - b) ]

$= x^{-2} (x^2+ 1)(x+1)(x-1)$               $[\frac{1}{a^m} = a^{-m}]$

If your question is x² - x - 2

Answer: x = 2   Or   x = -1

Solution:

= x² - x - 2

= x² - 2x + x -2

= x (x - 2) + 1 (x - 2)

= ( x - 2 ) ( x + 1 )

⇒ (x -2) = 0   Or    (x + 1) = 0

⇒ x = 2   Or   x = -1

Hope you understood.

Thank You.