Question

x2 + x = 2
$x2 + x = 2$
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Answer 1

Answer:

$x^2+x=2$

$x^2+x-2=0$

$x^2+2x-x-2=0$

$x(x+2)-1(x+2)=0$

$(x-1)(x+2)=0$

$x=1,-2$

$@rohangupta0424$

Answer 2

Answer:

$x^{2} +x=2\\\\x^{2} +x-2=0\\\\x^{2} +2x-x-2=0\\\\x(x+2)-1(x+2)\\\\(x + 2)(x-1) = 0\\\\\left[\begin{array}{c|c}x+2=0&x-1=0\\x=-2&x=1 \end{array}\right] \\\\\boxed{So, \: x \:can \: have \: 2 \: values \: -2 \: and \: 1}$

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