Math, asked by kdsb2007, 6 months ago

(x2-x-2)/x-2 + (2x2-x-1)/x-1 = (4x2+x-3)/x+1

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Answered by avdheshk278

Answer:

x2 – 2x = (–2) (3 – x) is a quadratic equation. (iii) (x ... (x – 2) (x + 1) = (x – 1) (x + 3) is not quadratic equation. ... x3 – 4x2 – x – 1 – x3 + 6x2 – 12x + 8 = 0

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$ok$

Answered by maheshgosai1126

Answer:

Here's Your Correct Answer

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(x2-x-2)/x-2 + (2x2-x-1)/x-1 = (4x2+x-3)/x+1 ​

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Please Mark Me As Brainliest For My Answer Please .

(x2-x-2)/x-2 + (2x2-x-1)/x-1 = (4x2+x-3)/x+1