Math, asked by mangeshavhad, 7 months ago

x2+x-20=0 solve in avayav padhatine sodva

Answers

Answered by Mansimehra23109

1

Answer:

x2+x-20=0

x2 +5x -4x -20=0

x(x+5) -4 (x+5) = 0

(x-4) (x+5) =0

x= 4,-5

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