Question

( x² + x - 20=0 ) solve the following quadratic equation​

Answer 1

Answer:

$x {}^{2} + x - 20 = 0 \\ x {}^{2} + 5x - 4x - 20 = 0 \\ x(x + 5) - 4(x + 5) = 0 \\ (x + 5)(x - 4) = 0 \\ \\ x = - 5 \\ x = 4$

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Answer 2

Answer:

x^2+x-20=0

x^2+5x-4x-20=0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

x=-5,x=4

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