Question

x²-x-(2k+2). put x=-4​

Answer 1

$= > {x}^{2} - x - (2k + 2) = 0 \\ on \: putting \: x = - 4 \\ = > {( - 4)}^{2} - ( - 4) - (2k + 2) = 0 \\ = > 16 + 4 - 2k - 2 = 0 \\ = > 2k = 20 - 2 \\ = > 2k = 18 \\ = > k = 9$

hope it will help u ✨☺️

Answer 2

GIVEN:

x=-4

TO FIND:

p(x) = x²-x-[2k+2]  

p(-4)=[-4]²-[-4]-[2k+2]

=16+4-2k-2=0

=20-2k-2=0

18-2k=0

18=2k

k=18/2

k=9

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