x2 (x + 2y)(x – 3y)
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x²(x+2y)(x-3y)
x²(x²-3xy+2xy-6y²)
=x⁴-3x³y+2x³y-6x²y²
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0
Answer:
Step-by-step explanation:
x2(x+2y)(x−3y)
=(x2(x+2y))(x+−3y)
=(x2(x+2y))(x)+(x2(x+2y))(−3y)
=x4+2x3y−3x3y−6x2y2
=x4−x3y−6x2y2
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