Question

x² - x-4/6 =5/3 please solve this​

Answer 1

Answer:

Easy

Step-by-step explanation:

$x^2\cdot \:6-x\cdot \:6-\frac{4}{6}\cdot \:6=\frac{5}{3}\cdot \:6$

$6x^2-6x-4=10$

$6x^2-6x-4-10=10-10$

$6x^2-6x-14=0$

$x_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:6\left(-14\right)}}{2\cdot \:6}$

$\sqrt{\left(-6\right)^2-4\cdot \:6\left(-14\right)}$

$x_{1,\:2}=\frac{-\left(-6\right)\pm \:2\sqrt{93}}{2\cdot \:6}$

$x_1=\frac{-\left(-6\right)+2\sqrt{93}}{2\cdot \:6},\:x_2=\frac{-\left(-6\right)-2\sqrt{93}}{2\cdot \:6}$

$\frac{-\left(-6\right)+2\sqrt{93}}{2\cdot \:6}$

$\frac{-\left(-6\right)-2\sqrt{93}}{2\cdot \:6}$

$x=\frac{3+\sqrt{93}}{6},\:x=\frac{3-\sqrt{93}}{6}$