Question

x²-x-5=0 factorise ​

Answer 1

Step-by-step explanation:

Given quadratic equation is x²-x-5=0

here, a = 1 , b = -1 , c = -5

the roots of a quadratic equation ax²+bx+c = 0 are x = -b ± √b²-4ac / 2a

=> x = -(-1) ± √(-1)²-4(1)(-5) / 2(1)

=> x = 1 ± √1+20 / 2

=> x = 1 + √21 / 2 or x = 1 - √21 / 2