Question

x² - x - 5 = 0 pls solve the equation I need it urgently ​

Answer 1

Answer:

Step-by-step explanation:

b²-4ac=-1²-4×1×-5

20

x=-b±√b²-4ac/2a

=1±√20/2

x=1+√20/2 & 1-√20/2

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Answer 2

Step-by-step explanation:

• Given quadratic equation

        $\mathbf{x^{2}-x-5=0}$

• On comparing the above equation with standard quadratic equation of $\mathbf{ax^{2}+bx+c=0}$

        So a = +1     ,   b = - 1 , c = - 5

• By using quadratic formula for solution of quadratic equation

        $\mathbf{x=\frac{-b\mp \sqrt{b^{2}-4ac}}{2a}}$

        $\mathbf{x=\frac{-(-1)\mp \sqrt{(-1)^{2}-4\times 1\times (-5)}}{2\times 1}}$

        $\mathbf{x=\frac{1\mp \sqrt{1+20}}{2}}$

        $\mathbf{x=\frac{1\mp \sqrt{21}}{2}}$

• So

        First solution of given equation are

        $\mathbf{x_{1}=\frac{1- \sqrt{21}}{2}}$

• Second solution of given equation are

        $\mathbf{x_{1}=\frac{1+ \sqrt{21}}{2}}$