Question

x2-x-6=0 in prime factroisation method

Answer 1

Answer:

x^2 - x - 6 = 0

=> x^2 - 3x + 2x -6 = 0

=> x (x - 3) + 2 (x - 3) = 0

=> (x-3) (x+2) = 0

therefore

x-3 = 0 or x+2 = 0

x = 3 or x = -2

Hope it helps

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