Question

x²-x-6=0 na componets sodho​

Answer 1

Answer:

${x}^{2} - x - 6 = 0$

${x}^{2} - (3 - 2)x - 6 = 0$

${x}^{2} - 3x + 2x - 6 = 0$

$x(x - 3) + 2(x - 3) = 0$

$(x - 3)(x + 2) = 0$

$(x - 3) = 0 \: \: and \: \: (x + 2) = 0$

$x = 3 \: \: and \: \: x = - 2$

Ans. 3 and -2

Hope it helps.

Answer 2

${x}^{2} - x - 6 = 0$

${x}^{2} - (3 - 2)x - 6 = 0$

${x}^{2} - 3x + 2x - 6 = 0$

$x(x - 3) + 2(x - 3)$

$(x - 3)(x + 2)$

$x - 3 = 0 \: \: \: so \: x = 3$

$x + 2 = 0 \: \: so \: \: x = - 2$