Math, asked by pulaha, 6 months ago

x2-x-600=0 solve for x​

Answers

Answered by srivaishnaviparamatm
0

Answer:

x²-x-600=0

(solve like terms and use transposition method)

(x²-x=x)

x-600=0

x=600+0

x=600

Sorry if its wrong

Answered by ajithameekhal
2

Answer:

Value of x is 25 or -24

Step-by-step explanation:

Method 1

  x²-x-600 = 0

      x²-x    = 600

adding (1/2)² on both sides

x²-x+(1/2)² = 600+(1/2)²

   (x-1/2)²  = 600+1/4

                = 600×4+1 / 4

                = 2400+1 / 4

                = 2401 / 4

    (x-1/2)² = 2401 / 4

     x-1/2   = √(2401 / 4)                             √2401 = 49 , √4 = 2

                =  ±49/2

   x  = 49/2 + 1/2       x = -49/2+1/2

       = 49+1  /  2           = -49+1 / 2

       = 50 / 2                = -48/2

       = 25                     = -24

 

Method 2

 x²-x-600 = 0

a=1 , b=-1 , c=-600

x = -b±√(b²-4ac) / 2a

√(b²-4ac)  = √(-1² - 4×1×-600)

               = √(1+2400)

               = √2401

               = 49

            x = -b±√(b²-4ac) / 2a

               = +1±49 / 2

 x = 1+49 / 2           x = 1-49 / 2

    = 50/2                   = -48/2

    = 25                      = -24

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