x2 + x - (a + 1)(a + 2) = 0 by factorisation
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Answer:
x = - a - 2 or a + 1
Step-by-step explanation:
⇒ x^2 + x - ( a + 1 )( a + 2 ) = 0
Spitting the middle term in such a manner so that product of term with x^2 and constant become equal.
Here, those parts are a + 2 and a + 1.
⇒ x^2 + x( 1 ) + ( a + 2 )( a + 1 ) = 0
⇒ x^2 + x[ a - a + 2 - 1 ] - ( a + 2 )( a + 1 ) = 0
⇒ x^2 + x[ ( a + 2 ) - ( a + 1 ) ] - ( a + 2 )( a + 1 ) = 0
⇒ x^2 + x( a + 2 ) - x( a + 1 ) - ( a + 2 )( a + 1 ) = 0
⇒ x[ x + a + 2 ] - ( a + 1 )[ x + a + 2 ] = 0
⇒ ( x + a + 2 )( x - a - 1 ) = 0
Values of x are :
x = - a - 2 or a + 1
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