Question

x²+x-(a+1)(a+2) = 0
Factorise

Answer 1

Hey there!



We have ,

x^2 + x - (a+1)(a+2) = 0

x^2 + x {(a+2 ) -(a+1) } - (a+1)(a+2) =0

{ x^2 + x (a+2)} -x (a +1) -(a + 1) (a+2)=0

x { x +(a+2) } - (a+1) { x+ (a+2)} =0

{x + (a+2) } { x - (a+1)} =0

x + (a +2) = 0 or , x - (a+1) =0

So, x = -(a+2) or, x = (a+1)


Hope it helps!