Question

x²+x-(a+1)(a+2)=0 solve this plz

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.

Explanation:

Given quadratic equation:

x²+x-(a+1)(a+2)=0

Splitting the middle term,weget

=>x²-(a+1)x+(a+2)x-(a+1)(a+2)=0

=>x[x-(a+1)]+(a+2)[x-(a+1)]=0

=>[x-(a+1)][x+(a+2)]=0

=>x-(a+1)=0Or x+(a+2)=0

=>x=(a+1)Orx=-(a+2)

Therefore,

x =(a+1)Orx=-(a+2)aretworootsof given quadratic equation.

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