x²+x-(a+1) (a+2)
factorise
Answers
Answered by
2
Answer:
Given x
2
+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)
x=
2a
−b±
b
2
−4ac
=
2(1)
−1±
1
2
−4{(a+2)(a+1)}
=
2
−1±
1−4{−(a
2
+3a+2)
x=
2
−1±
1+4a
2
+12a+8
=
2
−1±
4a
2
+12a+9
=
2
−1±
(2a+3)
2
=
2
−1±(2a+3)
∴x=
2
−1+2a+3
and x=
2
−1−2a−3
∴x=
2
2a+2
and x=
2
−2a−4
x=a+1x=−(a+2)
∴ The roots of x
2
+x−(a+2)(a+1)=0 are (a+1) and −(a+2)
Answered by
1
Answer:
X^2+x-a^2+3a+2
Put X=a then
a^2+a-a^2+3a+2
4a+2
4a=-2
a=-2/4
a=-1/2
Step-by-step explanation:
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