Question

x²+x-(a+2)(a+1) = 0​

Answer 1

Answer:

$Given x2+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)</p><p>x=2a−b±b2−4ac=2(1)−1±12−4{(a+2)(a+1)}=2−1±1−4{−(a2+3a+2)</p><p>x=2−1±1+4a2+12a+8=2−1±4a2+12a+9=2−1±(2a+3)2=2−1±(2a+3)</p><p>∴x=2−1+2a+3 and x=2−1−2a−3∴x=22a+2 and x=2−2a−4</p><p>x=a+1x=−(a+2)</p><p>∴ The roots of x2+x−(a+2)(a+1)=0 are (a+1) and −(a+2)</p><p></p><p>$

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