Question

x²+x-a(a+1)=0. find the roots of the equation

Answer 1

Answer:

Step-by-step explanation:

x^+x-a(a+1)=0

B^-4ac=0

1^-4(-a^-a)=0

1+4a^+4a

4a^+4a+1

4a^+(2a+2a)+1

4a^+2a+2a+1

2a(2a+1)+1(2a+1)

(2a+1)(2a+1)

a= -1/2, a= -1/2