x2-x(a+b)+k=0 find the value of k if x= a
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Answered by
29
Hi there !!
p(x) = x² - x(a+b) + k = 0
x = a
p(a) = a² - a (a+b) + k
a² - a² - ab + k = 0
k = ab
p(x) = x² - x(a+b) + k = 0
x = a
p(a) = a² - a (a+b) + k
a² - a² - ab + k = 0
k = ab
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Answered by
1
Answer:
k=ab
Explanation:
a=x
a^2-a(a+b)+k=0
a^2-a^2-ab+k=0
-ab+k=0
k=ab
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