x²-x=k(2x-1) ...........k=?
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answer of the question is 0 I think
Step-by-step explanation:
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Step-by-step explanation:
x²-x= k(2x-1)
=] x²-x= 2kx-k
=] x²+k= 2kx+x
=] x²+k = x{2k+1}
Through Hit- Trial Method ; we have :
if x=0 then k= 0
x=1 then k=1&½
x=2 then k=1&½
Now either. X can be 1 or 2 in both the cases k will be either 1&½
so the value of k can be 1 when x is 1 and ½ when x is 2
With the little information you gave ; this was most convenient and reasonable answer
Hope it Helps !
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