Math, asked by muskan8422, 9 months ago

x²×(x/y-y/x)×(y/x+x/y)×y²

Answers

Answered by mhanifa

Answer:

x⁴-y⁴

Step-by-step explanation:

x²×(x/y-y/x)×(y/x+x/y)×y²=

x²×((x²-y²)/yx)×((x²+y²)/xy)×y²=

x²y²×(x²-y²)×(x²+y²)/x²y²=

(x²-y²)×(x²+y²)= x⁴-y⁴

Answered by silentloffer

$\Huge{\bold{\mathrm{\underline{\red{ANSWER}}}}}$

${x}^{2} \times ( \frac{x}{y} - \frac{y}{x} ) \times ( \frac{y}{x} + \frac{x}{y} ) \times {y}^{2} \\ \\ \\ {x}^{2} \times ( \frac{ {x}^{2} - {y}^{2} }{xy} ) \times ( \frac{ {y}^{2} + {x}^{2} }{xy} ) \times {y}^{2} \\ \\ \\ {x}^{2} \times ( \frac{( {x}^{2} - {y}^{2})( {x}^{2} + {y}^{2}) }{ {x}^{2} {y}^{2} } ) \times {y}^{2} \\ \\ \\ \\ ( {x}^{2} - {y}^{2} )( {x}^{2} + {y}^{2} ) = > \\ \\ \\ = > {x}^{4} + {x}^{2} . {y}^{2} - {x}^{2} . {y}^{2} - {y}^{4} \\ \\ = > {x}^{4} - {y}^{4} \: \: ans...$

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