x² ×x²+3x-2+7x=18x⁴
Answers
Answered by
0
Answer:
xε(1,6)
Step-by-step explanation:
1≤x2+13x2−7x+8≤2
x2+13x2−7x+8−2(x2+1)≤0
(x2+1>0)
3x2−7x+8−2x2−2≤0
x2−7x+6≤0
x2−6x−x+6≤0
(x−1)(x−6)≤0
xε(1,6)
(ii)1≤x2+13x2−7x+8
x2+13x2−7x+8−(x2+1)≥0
3x2−7x+8−x2−x≥0
2x2−7x+7≥
D=b2−4ac=49−(4×2×7)<0
hencexεallrealnumbers
from(i)&(ii)
xε(1,6)
Answered by
0
Answer:
x^2 *x^2 = x^4
x^4 + 3x +7x -2 = 18x^4
x^4 + 10x -2 = 18x^4
10x -2 = 18x^4 - x^4 = 17x^4
Step-by-step explanation:
BRAINLIEST plz plz
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