Math, asked by IRONMAN1999Y, 8 months ago

x² ×x²+3x-2+7x=18x⁴​

Answers

Answered by DATHADITYA
0

Answer:

xε(1,6)

Step-by-step explanation:

1≤x2+13x2−7x+8≤2

x2+13x2−7x+8−2(x2+1)≤0

(x2+1>0)

3x2−7x+8−2x2−2≤0

x2−7x+6≤0

x2−6x−x+6≤0

(x−1)(x−6)≤0

xε(1,6)

(ii)1≤x2+13x2−7x+8

x2+13x2−7x+8−(x2+1)≥0

3x2−7x+8−x2−x≥0

2x2−7x+7≥

D=b2−4ac=49−(4×2×7)<0

hencexεallrealnumbers

from(i)&(ii)

xε(1,6)

Answered by beherags
0

Answer:

x^2 *x^2 = x^4

x^4 + 3x +7x -2 = 18x^4

x^4 + 10x -2 = 18x^4

10x -2 = 18x^4 - x^4 = 17x^4

Step-by-step explanation:

BRAINLIEST plz plz

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