x²(x²+x+1)=x⁴+x³-x²+3x-1
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Answer:
1/3
Step-by-step explanation:
1 Expand.
{x}^{4}+{x}^{3}+{x}^{2}={x}^{4}+{x}^{3}+{x}^{2}+3x-1
x
4
+x
3
+x
2
=x
4
+x
3
+x
2
+3x−1
2 Cancel {x}^{4}x
4
on both sides.
{x}^{3}+{x}^{2}={x}^{3}+{x}^{2}+3x-1
x
3
+x
2
=x
3
+x
2
+3x−1
3 Cancel {x}^{3}x
3
on both sides.
{x}^{2}={x}^{2}+3x-1
x
2
=x
2
+3x−1
4 Cancel {x}^{2}x
2
on both sides.
0=3x-1
0=3x−1
5 Add 11 to both sides.
1=3x
1=3x
6 Divide both sides by 33.
\frac{1}{3}=x
3
1
=x
7 Switch sides.
x=\frac{1}{3}
x=
3
1
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