Question

x²+x³+x⁴+x⁵=60 find the value of x.

Answer 1

108.4

we will add the powers

it will x14=60

x=14underroot60

x=108.44

$(a + b + c) {}^{2}$

Answer 2

using trial and error method

lets assume x=1

LHS

1²+1³+1^4+1^5

1+1+1+1

=4

RHS

60

LHS≠RHS

therefore x=1 is not the solution

lets assume x=2

LHS

2²+2³+2^4+2^5

=4+8+16+32

=12+48

=60

RHS

60

LHS=RHS

therefore x=2 is the solution .