x²+xy =28
y² +xy =21
(x,y)=?
Answers
Answered by
1
x^+xy=28
y^+xy=21
(x,y)=?
=588
Answered by
0
Answer:
x = 4 , y = 3
Step-by-step explanation:
x^2 + xy = 28
x * x + x * y = 28
x (x + y) = 28
y^2 + xy = 21
y * y + x * y = 21
y (x + y) = 21
x (7) = 28
x = 28/7
= 4
y (7) = 21
y = 21/7
= 3
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