Math, asked by meghnasuru1122, 4 months ago

x²+xy =28
y² +xy =21
(x,y)=?​

Answers

Answered by kolponapaul980986
1

x^+xy=28

y^+xy=21

(x,y)=?

=588

Answered by sohamsaimishra
0

Answer:

x = 4 , y = 3

Step-by-step explanation:

x^2 + xy = 28

x * x + x * y = 28

x (x + y) = 28

y^2 + xy = 21

y * y + x * y = 21

y (x + y) = 21

x (7) = 28
x = 28/7
  = 4

y (7) = 21
y = 21/7
  = 3

Similar questions