Question

(x2-xy)3 ..?.................
.............

Answer 1

Answer:

We have y−x=1 or y=1+x

Substitute y=1+x in the equation we get

x2+y2−xy=3

⇒x2+(1+x)2−x(1+x)=3

⇒x2+x2+2x+1−x−x2−3=0

⇒x2+x−2=0

⇒(x−1)(x+2)=0

∴x=1,−2

When x=1⇒y=1+x=1+1=2

When x=−2⇒y=1+x=1−2=−1

∴{1,2} and {−2,−1} are the solutions