Math, asked by kkshrivastavajb9967, 8 months ago

X2+xy+9x+9y...factorise by regrouping

Answers

Answered by layasweetie
41

Step-by-step explanation:

x^2+xy+9x+9y

(x^2+9) (xy+9y)

x(x+9)y(x+9)

(x+y) (x+9)

Answered by hukam0685
37

Step-by-step explanation:

Given:

 {x}^{2}  + xy + 9x + 9y \\

To find: Factorisation by grouping

Solution:

To factorise the given expression

by inspection,one can see that,

x is common in first two terms and 9 in last two terms

 {x}^{2}  + xy + 9x + 9y \\  \\ =  x(x + y) + 9(x + y) \\  \\  =( x + y)(x + 9) \\  \\\bold{ {x}^{2}  + xy + 9x + 9y  =( x + y)(x + 9)} \\  \\

Hope it helps you.

To learn more from brainly:

1)a^6+4a^3-1 find factor

https://brainly.in/question/4178145

2)use factors theirm to prove that x+a is a factor of (x^n+ a^n) for any odd positive integer n

https://brainly.in/question/4644815

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