x2+xy+x=12 and y2+xy+y=18,find x-y
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Hi ,
x² + xy + x = 12 ----( 1 )
y² + xy + y = 18 ----( 2 )
add equations ( 1 ) and ( 2 ) , we get
x² + 2xy + y² + x + y = 30
( x + y )² + ( x + y ) - 30 = 0
( x + y )² + 6( x + y ) - 5( x + y ) - 30 = 0
( x + y ) [ x + y + 6 ] - 5 ( x + y + 6 ) = 0
( x + y + 6 ) ( x + y - 5 ) = 0
Therefore ,
x + y + 6 = 0 or x + y - 5 = 0
x + y = -6 or x + y = 5
sjuveria16:
Thanks
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