(x²+xy-x²)×(x²-xy+x²)
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Answer:
How would you simplify (x² - y²) / (x² + xy)?
(x^2 - y^2) / (x^2 + xy)
For the top part, you need to recognize that (x^2 - y^2) is a product of a conjugate. Please look up the term and know how to identify conjugate. That is it factors down to (x - y) * (x + y). So the first step will result in :
[(x - y) * (x + y)] / (x^2 + xy)
The next step is to factor the bottom half. There are x’s on both parts. So factor out the x and get: x (x + y). Here is the result of the next step:
[(x - y) * (x + y)] / [x (x + y)]
The final step is to reduce like terms that are on top and the bottom. That is (x + y). So you are left as the FINAL answer:
(x - y) / x
If x is not = to 0.
How does (x³+y³) become=(x+y) (x²-xy+y²)?
What does x²+y²=xy represent?
What is X²/9-y²/16?
What is a solution for (x²-x) y²+y-(x²+x)?
If x² + y² = 6 and xy = 2, what is the value of (x + y) ²?
Factor the numerator (x2−y2), using the difference of squares rule, so it becomes (x+y)(x−y) .
Factor the denominator (x2+xy) , by pulling out the GCF of (x2 and xy) , which is x . That factors into x(x+y) .
Now the fraction x2−y2x2+xy has been factored into (x+y)(x−y)x(x+y) .
Cancel out the like factors on opposite sides. The (x+y) appears exactly once in the numerator and once in the denominator, so those are like factors, and they cancel those out. Therefore, (x+y)(x−y)x(x+y) becomes (x−y)x as the simplified fraction.
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Simplify (x² - y²) / (x² + xy)?
This should be fairly obvious if you have learnt about the difference between two squares.
You can obviously take the common factor x from the denominator. The difference between squares in the numerator can be factored as (x−y)(x+y) . So long as x≠−y , you can cancel x+y .
I leave the rest to you so that you will learn by doing.
(x² - y²) / (x² + xy)
(x+y)(x-y)/x(x+y)
After cancelling (x+y)
(x-y)/x or 1-(y/x)
How do I factorise x²+y²?
Can you simplify (x/2 + y/3) ² - (x/2- y/3) ³?
How do I simplify (3÷x_y) _ (1÷ x+y)?
How do I simplify (x+1) ²?
How can I simplify xy+x/y+1?
(x² - y²) / (x² + xy)
((x+y)(x-y))/ (x(x+y) Factor the numerator and denominator
(x-y)/x The term x+y cancels
(x-y)/x is the answer
If x is not = to 0.
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We can expand x^2 - y^2 into (x+y)(x-y)
Next, we can simply x^2 + xy into x(x+y)
Then we remove common terms(x+y) to get (x-y)/x
(x+y)(x−y)/(x(x+y))
(x−y)/x
If x is not = to 0.
x^2-y^2 = (x+y)(x-y)
x^2 + xy = x(x+y)
therefore results is (x+y)(x-y)/[x(x+y)]
= (x-y)/x
(x-y)(x+y)/(x+x)(x+y); The two “(x+y)”’s cancel each other. Now it’s reduced to (x-y)/ (x+x)
Provided x (ne) 0 and x (ne) -y, (x^2 - y^2)/(x^2 + xy) simplifies to 1 - (y/x). (ne) means “not equal”.
(x^2 - y^2) / (x^2 + xy) =
(x+y)(x-y)/x(x+y) =
(x-y)/x
How does (x³+y³) become=(x+y) (x²-xy+y²)?
What does x²+y²=xy represent?
What is X²/9-y²/16?
What is a solution for (x²-x) y²+y-(x²+x)?
If x² + y² = 6 and xy = 2, what is the value of (x + y) ²?
How do I factorise x²+y²?
Can you simplify (x/2 + y/3) ² - (x/2- y/3) ³?
How do I simplify (3÷x_y) _ (1÷ x+y)?
How do I simplify (x+1) ²?
How can I simplify xy+x/y+1?
How do you find(x,y) such that x²-y²=1 and x²+y²=1?
How do you simplify x+(x+y) =x+y?
If x+y+z = 0 , what is (x²+xy+y²) =?
How would you factor x²±xy+y² using complex numbers?
If x-x = x/x, what is x?