Question

X2+y2=16 and xy=15 so find out x+y?

Answer 1

x² + y² = 16

And xy = 15

x + y =?

Using identity

(x +y)²= x² +2xy + y²

(x +y)² = 16 +2(15)

(x +y)² = 16 +30

(x +y)² = 46

x +y = ±√46

Therefore the value of x+y = ±√46

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Answer 2

x+y= $\sqrt{46}$

The algebraic equation consists of both variables and constants. Its combination with mathematical operations is said to be an algebraic expression. A linear equation is ax+b=0. The given equations will be simplified using this expression and also finding out the value of x+y.

Given equations are,

X2+y2=16 and xy=15

Let us consider x as a and y as b.

Substitute in the formula,

(a+b)^2=a^2+b^2+2ab

(x+y)^2=x^2+y^2+2xy

(x+y)^2=16+2(15)

(x+y)^2=16+30

(x+y)^2= 46

(x+y)    = $\sqrt{46}$