Math, asked by dorarednam1, 7 months ago

(x²+y²)²-(z)²-4x²y²​

Answers

Answered by rtsundarrajan
0

Answer:

(x²+y²)²-(z)²-4x²y²

{x^4 + 2x²y² + y^4} - z² - 4x²y²

x^4 -2x²y² + y^4 - z²

(x² - y²)^2 - z²

Answered by vaibhavshukla97
0

Step-by-step explanation:

(x²+y²)²-(z)²-4x²y²

=()²+()²+2x²y²-z²-4x²y²

=()²+()²-z²-2x²y²

=(x²+y)²-z²

=(x²+y²+z)(x²+y²-z)

hope this helps you

Similar questions