Question

(x² + y²- 2²)^2 - (x² - y² +Z²)^2=​

Answer 1

Answer:

(i) Given : (x + y + z)²+ (x + y/2 + z/3)² - (x/2 + y/3 + z/4)² By using an identity (a + b + c)² = a² + b² + c² + 2ab + 2 bc + 2 ca) = [(x² + y²

Answer 2

Answer:

{(x^2×2)+(y^2×2)-(2^2×2)} - {(x^2×2)-(y^2×2)+(Z^2×2)}

(x^4+y^4-2^4) - (x^4-y^4+Z^4)

x^4+y^4-2^4 -x^4+y^4 -z^4

2y^4-z^4-2^4