x2 + y2= 25xy, then prove that 2 log(x+y)=3log3+logx+logy
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x²+y²=25xy
Start with adding 2xy on both sides of the given equation
x²+y²+2xy=27xy
Simplify
[x+y]²=27xy
Now take log on both sides
log[x+y]²=log27xy
2log[x+y]=log3³+log x+log y
2 log[x+y]=3log3+logx+logy
x²+y²=25xy
Start with adding 2xy on both sides of the given equation
x²+y²+2xy=27xy
Simplify
[x+y]²=27xy
Now take log on both sides
log[x+y]²=log27xy
2log[x+y]=log3³+log x+log y
2 log[x+y]=3log3+logx+logy
Suprihari:
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