x²+y²=25xy then prove that 2log(x+y)=3log3+logx+logy. prove this please fast
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Hi...☺
Here is your answer...✌
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x²+y² = 25xy ___(1)
Now,
We know that,
(x+y)² = x²+y²+2xy
(x+y)² = 25xy+2xy ___From (1)
(x+y)² = 27xy
Taking Logarithm both sides
log(x+y)² = log(27xy)
2log(x+y) = log27 + logx + logy
2log(x+y) = log(3³) + logx + logy
2log(x+y) = 3log3 + logx + logy
HENCE PROVED ✌
Here is your answer...✌
==================================
x²+y² = 25xy ___(1)
Now,
We know that,
(x+y)² = x²+y²+2xy
(x+y)² = 25xy+2xy ___From (1)
(x+y)² = 27xy
Taking Logarithm both sides
log(x+y)² = log(27xy)
2log(x+y) = log27 + logx + logy
2log(x+y) = log(3³) + logx + logy
2log(x+y) = 3log3 + logx + logy
HENCE PROVED ✌
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